A rod of weight 
is supported by two parallel knife edges 
and 
and is in equilibrium in a horizontal position. The knives are at a distance 
from each other. The centre of mass of the rod is at distance 
from 
. The normal reaction on 
is
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
D
As the weight 
balances the normal reactions.
Upward force = downward force
So, weight, 
… (i)
Now, balancing torque about the COM,
i.e. anti-clockwise momentum
= clockwise momentum
Putting the value of 
from Eq. (i), we get
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